Math, asked by sanidhya13, 1 year ago

if sin theta = cos (theta -45 )theta &(theta - 45) are acute angle find the value of theta?

Answers

Answered by kunal0912
91
Sin (theta) = cos (theta -45)

so, Cos (90-theta) = cos (theta -45)       [Cos(90-A) = SinA]
 Hence, 90 - theta = theta - 45
           so, theta = 135/2 = 67.5°

Anonymous: nice
Answered by isyllus
55

Answer:

The value of theta (\theta) is 67.5°

Step-by-step explanation:

We are given an equation,

\sin\theta=\cos(\theta-45^{\circ})

where,  \theta and  (\theta-45^{\circ}) are acute angle.

using formula, \sin\theta = \cos(90^{\circ}-\theta)

\cos(90^{\circ}-\theta)=\cos(\theta-45^{\circ})

90^{\circ}-\theta=\theta-45^{\circ}

2\theta=90^{\circ}+45^{\circ}

\theta=\frac{135^{\circ}}{2}=67.5^{\circ}

Thus, The value of theta (\theta) is 67.5°

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