Question

if sin theta + cos theta equal to P and secant theta + cosec theta equal to QR so that PQ into p square minus 1 equal to 2 p​

Answer 1

answer: -

P=sinθ+cosθ and q=secθ+cosecθ

q(p²-1)

=(secθ+cosecθ)[(sinθ+cosθ)²-1]

=(1/cosθ+1/sinθ)(sin²θ+2sinθcosθ+cos²θ-1)

={(sinθ+cosθ)/sinθcosθ}(2sinθcosθ) [ Since, sin²θ+cos²θ=1]

=2(sinθ+cosθ)

=2p (Proved)

Answer 2

Hi.. Refer above attachment for the answer..