if sin theta + cos theta equal to root 2 then theta is equal to
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sin θ + cos θ = √2
Squaring on both sides,
(sin θ + cos θ)² = √2²
sin²θ + cos²θ + 2sinθ.cosθ = 2
1 + 2sinθ.cosθ = 2
2sinθ.cosθ = 2-1
2sinθ.cosθ = 1
sinθ.cosθ = ½
sinθ.cosθ = (1/√2) × (1/√2)
sinθ = cos θ = 1/√2
θ = 45°
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