if sin theta + cos theta equals to p and sin theta minus cos theta equals to Q then
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sin theta + cos theta equals to p and sin theta minus cos theta equals to Q then
Given,
sin theta + cos theta = p
squaring on both sides, we get,
(sin theta + cos theta)² = (p)²
sin² theta + cos² theta + 2sin theta × cos theta = p² .........(1)
sin theta - cos theta = q
squaring on both sides, we get,
(sin theta - cos theta)² = (q)²
sin² theta + cos² theta - 2sin theta × cos theta = q² ............(2)
adding equations (1) and (2), we get,
sin² theta + cos² theta + 2sin theta × cos theta + sin² theta + cos² theta - 2sin theta × cos theta = p² + q²
2 (sin² theta + cos² theta) = p² + q²
as we know that, sin² theta + cos² theta = 1
2 (1) = p² + q²
∴ p² + q² = 1
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