Question

if sin theta + cos theta equals to p then find the value of sin theta minus cos theta

Answer 1

Answer:

LHS :

q(p

2

−1)

=(secθ+cosec θ)[(sinθ+cosθ)

2

−1]

=(

cosθ

1

+

sinθ

1

)(2sinθcosθ)

=(

sinθcosθ

sinθ+cosθ

)(2sinθcosθ)

=2(sinθ+cosθ)=2p = RHS

Answer 2

Answer:

$\textit {root2sintheta ,2p}$