Question

if sin theta + cos theta equals to root 2 then evaluate 10 theta + cot theta

Answer 1

sin@+cos@=√2 so squaring both sides
(sin@+cos@)^2= 1+ 2 sin@×cos@
2-1=2sin@cos@ so sin@cos@=1/2 ... now tan@+ cot@= (sin@/cos@)+ (cos@/sin@)
= (sin^2@+cos^2@)/ sin@cos@= 2