Math, asked by Manas2007, 1 year ago

If sin theta = cos theta .Find the value of 2 tan^2 theta+sin ^2 theta -1

Answers

Answered by ayushi1552
98
3/2 is the answer.....
Attachments:
Answered by parmesanchilliwack
55

Answer: \frac{3}{2}

Step-by-step explanation:

Here,

sin\theta = cos\theta

\implies \frac{sin\theta}{cos\theta}=1

\implies tan\theta = 1

\implies \theta = 45^{\circ}

Now,

2 tan^2 \theta+sin^2 \theta -1

=2 tan^2 45^{\circ}+ sin^2 45^{\circ} -1

=2\times 1 + (\frac{1}{\sqrt{2}})^2-1

=2+\frac{1}{2}-1

=\frac{4+1-2}{2}=\frac{3}{2}

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