If sin theta = cos theta, find the value of 3 tan theta+ 2 sin2 theta- 1
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Answer:
Sin theta =cos theta
Sin 45=cos 45
So,theta =45
Then,
3tan square theta +2sin Square theta - 1=
3(1)^2+2(1/root2)^2-1
3*1+2*1/2-1
3+1-1
3
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