Math, asked by mp630899, 7 months ago

if sin theta =cos theta find value of theta​

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Answered by Anonymous
3

{\red {{\bold{ \huge \dag }}\bold {\huge{{\mathcal {\underline{Answer}}}} \dag}}}

 \bold{sin \theta = cos \theta}

 \longrightarrow \: tan \theta = 1

 \longrightarrow \: tan \theta  =  \: tan 45 \degree

 \longrightarrow \boxed {\bold {\mathfrak{ \theta  = 45 \degree}}}

HOPE THIS IS HELPFUL...

Answered by InfiniteSoul
3

Given that :-

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{\bold{Sin\theta = Cos\theta}}

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Now :-

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\sf :\implies \:{\bold{\dfrac{Sin\theta}{Cos\theta} = 1 }}

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\sf{\red{\boxed{\bold{tan\theta = \dfrac{Sin\theta}{cos\theta}}}}}

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\sf:\implies \:{\bold{tan\theta = 1 }}

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From trigonometric value table :-

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\sf{\red{\boxed{\bold{tan45 = 1 }}}}

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\sf :\implies\: {\bold{tan\theta = tan 45}}

\sf:\implies\: {\bold{\theta = 45 }}

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\sf{\underline{\huge{\boxed{\bold{More\: to \: explore }}}}}

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\Large{ \begin{tabular}{|c|c|c|c|c|c|} \cline{1-6} \theta & \sf 0^{\circ} & \sf 30^{\circ} & \sf 45^{\circ} & \sf 60^{\circ} & \sf 90^{\circ} \\ \cline{1-6} $ \sin $ & 0 & $\dfrac{1}{2 }$ & $\dfrac{1}{ \sqrt{2} }$ & $\dfrac{ \sqrt{3}}{2}$ & 1 \\ \cline{1-6} $ \cos $ & 1 & $ \dfrac{ \sqrt{ 3 }}{2} } $ & $ \dfrac{1}{ \sqrt{2} } $ & $ \dfrac{ 1 }{ 2 } $ & 0  \\ \cline{1-6} $ \tan $ & 0 & $ \dfrac{1}{ \sqrt{3} } $ & 1 & $ \sqrt{3} $ & $ \infty $    \\ \cline{1-6} \cot & $ \infty $ &$ \sqrt{3} $ &  1 &  $ \dfrac{1}{ \sqrt{3} } $ &0 \\  \cline{1 - 6} \sec & 1 & $ \dfrac{2}{ \sqrt{3}} $ & $ \sqrt{2} $ & 2 & $ \infty $ \\  \cline{1-6} \csc & $ \infty $ & 2 & $ \sqrt{2 } $ & $ \dfrac{ 2 }{ \sqrt{ 3 } } $ & 1  \\  \cline{1 - 6}\end{tabular}}

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