if sin theta + cos theta is equal to M and sec theta + cos theta is equal and then n(m+1)(m-1)?
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sinθ+cosθ=M
secθ+cosθ=N
n(m+1)(m-1)
=n(m²+m-m-1)
=n(m²-1)
=secθ+cosθ(sinθ+cosθ)²-1
= secθ+cosθ(sin²θ +cos²θ-2sinθcosθ-1)
= secθ+cosθ(1-1- 2sinθcosθ)
= secθ+cosθ(-2sinθcos)
hope helped!
sinθ+cosθ=M
secθ+cosθ=N
n(m+1)(m-1)
=n(m²+m-m-1)
=n(m²-1)
=secθ+cosθ(sinθ+cosθ)²-1
= secθ+cosθ(sin²θ +cos²θ-2sinθcosθ-1)
= secθ+cosθ(1-1- 2sinθcosθ)
= secθ+cosθ(-2sinθcos)
hope helped!
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