Question

if sin theta + cos theta is equal to root 2 cos theta, bracket theta is not equal to 90 degree bracket close then the value of tan theta is​

Answer 1

Answer:

$\tan(theta) = \sqrt{2} - 1$

Step-by-step explanation:

For step by step explaination refer to the attachment....

Answer 2

Answer:

$tan\alpha =\sqrt{2}-1$

Step-by-step explanation:

Given that-

$Sin\alpha + Cos\alpha =\sqrt{2}Cos\alpha$

Dividing by cosα on both sides-

$\dfrac{Sin\alpha }{Cos\alpha } + \dfrac{Cos\alpha }{Cos\alpha }  = \dfrac{\sqrt{2}Cos\alpha  }{Cos\alpha }$

But $\dfrac{Sin\alpha }{Cos\alpha } =tan\alpha$

So, $tan\alpha + 1 =\sqrt{2}$

$tan\alpha =\sqrt{2}-1$