Question

if sin theta + cos theta is root 2 then evaluate sin theta - cos theta​

Answer 1

Answer:

let there be A

sinA + cosA=√2

sinA - cosA=?

sin^2+cos^2=1 ------ identity

(sinA- cosA)(sinA+cosA)=1

(sinA- cosA)√2=1

sinA- cosA=1/√2.