Math, asked by srineetha, 1 year ago

if sin theta + cos theta =K and cosec + sec =J then what is the relationship between K and J whether exist or not​

Answers

Answered by vk109497
0

Answer:

Given: 9 sin θ + 40 cos θ= 41

⇒ 9sinθ = 41 – 40 cosθ …(i)

Squaring both sides, we get

⇒ 81sin2 θ = 1681+1600 cos2 θ – 2(41) (40cos θ) [∵ (a – b)2 =a2 +b2 –2ab]

⇒ 81 (1– cos2 θ) =1681+1600 cos2 θ – 3280cosθ

⇒ 81 – 81cos2 θ = 1681 +1600cos2 θ – 3280 cosθ

⇒ 1681cos2 θ –3280cos θ +1600 = 0

⇒ (41)2 cos2 θ – 2(41) (40cos θ) + (40)2 = 0

⇒ (41cos θ – 40 )2 = 0

Now, putting the value of cos θ in Eq. (i), we get

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Answered by lublana
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Yes, exist

\frac{k}{J}=sin\theta cos\theta

Step-by-step explanation:

sin\theta+cos\theta=k

cosec\theta+sec\theta=J

We know that

cosec\theta=\frac{1}{sin\theta}

sec\theta=\frac{1}{cos\theta}

Using the formula

\frac{1}{sin\theta}+\frac{1}{cos\theta}=J

\frac{sin\theta+cos\theta}{sin\theta cos\theta}=J

Substitute the value

\frac{k}{sin\theta cos\theta}=J

\frac{k}{J}=sin\theta cos\theta

This is required relationship between K and J.

#Learns more:

https://brainly.in/question/14794823:Satwik

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