Question

If sin theta + cos theta = m and sec theta + cosec theta = n then what is the relationship between these two?

Answer 1

Answer:

Step-by-step explanation:

Wdhat are you saying

Answer 2

Answer:

Step-by-step explanation:

Given that,

sin theta + cos theta= m, sec theta + cosec theta = n.

Consider LHS

n(m^2 - 1)

(sec\theta + cosec\theta)[(cos\theta + sin\theta)^2 - 1]

(sec\theta + cosec\theta)[cos^2 \theta + sin^2 \theta + 2sin\theta cos\theta - 1]

(sec\theta + cosec\theta)[2sin\theta cos\theta] since {cos^2 \theta + sin^2 \theta = 1}

sec\theta . 2sin\theta cos\theta + cosec\theta . 2sin\theta cos\theta

2sin\theta + 2 cos\theta

2[sin\theta + cos\theta]

= 2m