Question

If sin theta + cos theta = p and sec theta + cosec theta = q, then prove that q ( p^2 - 1 ) = 2p

Answer 1

Hey friend here is your answer
hope it's helps ☺☺

Answer 2

Answer:

Step-by-step explanation:

First the statement q(p2-1)=2p is not PROVEN, so you cant add values of p and q to it. I have used (a) instead of theta.

We are given sina + cosa=p

Lets square both the sides

(sina + cosa)2=p2 (after solving you get this below)...

sin2a + cos2a + 2sinacosa=p2

@use identity sin2a +cos2a=1

Replace value

1 + 2 sinacosa = p2

2sinacosa = p2-1

Now we have to just sole q in such a way that it equals to sinacosa

seca + coseca = q

1/cosa + 1/sina = q

take lcm

sina + cosa/cosasina = q

Now replace sina + cosa to p

p/cosasina=q

p/q= cosa sina

Take the above value and replace it in p2-1= 2cosa sina

p2-1= 2p/q

q(p2-1)=2p

Bingo solved

Hope it helps!!!!