If sin theta + cos theta = root 2 sin (90 - theta) show that cot Theta = root 2 +1
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Answer:
Let theata be A
sinA + cosA root 2 cos (90-A)
SinA +cosA= root 2 sinA
CosA = root 2sinA - sinA
CosA = sinA (root - 1)
CosA/sinA =(root - 2)
So, cotA= root 2 -1
hope it helps u....
Answered by
0
Answer:
Step-by-step explanation:
Let theata be A
sinA + cosA root 2 cos (90-A)
SinA +cosA= root 2 sinA
CosA = root 2sinA - sinA
CosA = sinA (root - 1)
CosA/sinA =(root - 2)
So, cotA= root 2 -1
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