If Sin theta +cos theta =root 2 then what is the value of theta?
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Answer:
θ = 45°
Step-by-step explanation:
Sinθ+Cosθ=√2
Or, (Sinθ+Cosθ)²=(√2)² [ By square both sides]
Or, Sin² + Cos² + 2 Sinθ Cosθ = 2
Or, 1+ 2 Sinθ. Cosθ = 2 [ as, Sin² + Cos² = 1]
Or, 2 Sinθ Cosθ = 2—1
Or, Sin 2θ = 1 [as, Sin 2θ = 2 Sinθ Cosθ ]
Or, Sin 2θ = Sin 90° [ as the value of Sin 90°= 1]
Or, 2θ = 90° [ Dividing Sin from both sides ]
Or, θ = 90°÷ 2 = 45°
So the value of θ is 45°
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