If sin theta + cos theta = root2 sin (90-theta). find cot theta
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Answered by
88
sin theta+cos theta=root2cos theta
as,sin(90-theta)=cos theta
sin theta=root2cos theta-cos theta
sin theta=cos theta(root2-1)....eq1
cot theta=cos theta/sin theta..
so cot theta=cos theta/cos theta(root2-1)...from eq 1...
=1/root2-1..=1/1.4-1..=1/0.4=5/2ans
as,sin(90-theta)=cos theta
sin theta=root2cos theta-cos theta
sin theta=cos theta(root2-1)....eq1
cot theta=cos theta/sin theta..
so cot theta=cos theta/cos theta(root2-1)...from eq 1...
=1/root2-1..=1/1.4-1..=1/0.4=5/2ans
Answered by
7
sin theta+cos theta=root2cos theta
as,sin(90-theta)=cos theta
sin theta=root2cos theta-cos theta
sin theta=cos theta(root2-1)....eq1
cot theta=cos theta/sin theta..
so cot theta=cos theta/cos theta(root2-1)...from eq 1...
=1/root2-1..=1/1.4-1..=1/0.4
=5/2
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