if sin theta -cos theta =root2 then prove that sin theta =cos theta
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let theta be 45°
sin 45° - cos 45° =√2
1/√2-1/√2=√2
2/√2=√2
√2=√2. ---------(1)
From (1) sin theta = cos theta
sin 45° = cos 45°
1/√2=1/√2
HENCE PROVED
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sin 45° - cos 45° =√2
1/√2-1/√2=√2
2/√2=√2
√2=√2. ---------(1)
From (1) sin theta = cos theta
sin 45° = cos 45°
1/√2=1/√2
HENCE PROVED
I HOPE IT'S HELP YOU
MAKE ME BRAINLIEST
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