If sin theta+cos theta=root2,then what is theta?
Answers
Answered by
103
Hi friend...
sin θ + cos θ = √2
Squaring on both sides,
(sin θ + cos θ)² = √2²
sin²θ + cos²θ + 2sinθ.cosθ = 2
1 + 2sinθ.cosθ = 2
2sinθ.cosθ = 2-1
2sinθ.cosθ = 1
sinθ.cosθ = ½
sinθ.cosθ = (1/√2) × (1/√2)
sinθ = cos θ = 1/√2
θ = 45°
Hope it helps
sin θ + cos θ = √2
Squaring on both sides,
(sin θ + cos θ)² = √2²
sin²θ + cos²θ + 2sinθ.cosθ = 2
1 + 2sinθ.cosθ = 2
2sinθ.cosθ = 2-1
2sinθ.cosθ = 1
sinθ.cosθ = ½
sinθ.cosθ = (1/√2) × (1/√2)
sinθ = cos θ = 1/√2
θ = 45°
Hope it helps
jamitawsif9:
thank a lot bro
Answered by
30
Hey,
Thanks for asking this question.
Please refer to the file that I have attached.
I have solved the question step by step and got the value of theta, which comes
or 45 degree.
Hope my answer helps.
Thanks for asking this question.
Please refer to the file that I have attached.
I have solved the question step by step and got the value of theta, which comes
or 45 degree.
Hope my answer helps.
Attachments:
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