If sin theta × cos theta + sin theta + cos theta = -1 then find the value of sin square theta + sin theta + 1
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Sin(theta) cos(theta) +sin(theta) +cos (theta) +1=0
[Sin (theta)+1][cos (theta) +1]=0
Sin (theta) +1=0
Sin^2 (theta) +sin (theta) +1
=(-1)^2 - 1+1=0
=1
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