If sin theta = cos theta then find the value of 3tan²theta-1
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sin theta = cos theta
so, sin theta = sin (90-theta) [since cos theta = sin90-theta]
so, theta = 90-theta
so, 2theta = 90
so, theta = 45
therefore, tan theta = 1
so, tan^2 theta = 1
and, sin theta =1/(2^1/2)
so, sin^2 theta = 1/2
Therefore, 3tan2 theta + 2 sin2 theta - 1 = 3(1) + 2(1/2) - 1
= 3 +1 -1
=3
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