Math, asked by ykrishnapz582, 1 year ago

if sin theta + cos theta = under root 2 cos (90 - theta) , determine the value of cot theta

Answers

Answered by rohitkumargupta
460
HELLO DEAR,

LET THETA = ALPHA

 \sin( \alpha )  +  \cos( \alpha )  =  \sqrt{2}  \cos( 90 - \alpha )  \\  \\   \sin( \alpha )  +  \cos( \alpha )   =  \sqrt{2}  \sin( \alpha )  \\  \\    \cos( \alpha )   =   \sqrt{2}  \sin( \alpha )  -  \sin( \alpha )  \\  \\   \cos( \alpha )  =  \sin \alpha ( \sqrt{2}  - 1) \\  \\  \frac{ \cos( \alpha ) }{ \sin( \alpha ) }  = ( \sqrt{2}  - 1) \\  \\   \cot( \alpha )  = ( \sqrt{2}  - 1)
I HOPE ITS HELP YOU DEAR,
THANKS
Answered by sharanadityadev
167

Hope its clear

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