Question

If sin theta + cos theta = x, then sin⁶ theta + cos ⁶theta = 1/4[4–3(x² -1)²] for
(A) All real x
(B) x² < =2
(C) x² >=2
(D) None of these​

Answer 1

Answer:

none of these

Step-by-step explanation:

sinthita6+costhita6 =1/4[4-3(x2-1)2

(sin³thita)2+(cos3thita)2= 1

Answer 2

Answer:

none of these

Step-by-step explanation:

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