Question

if sin theta=cos2 theta,then find cot3 theta, theta is being a acute angle​

Answer 1

Answer:

$\sin( \alpha ) = \cos(2 \alpha ) \\ \\ \sin( \alpha ) = 1 - 2 {sin}^{2} ( \alpha ) \\ \\ sin \alpha = - 1, \frac{1}{2} \\ \\ \alpha = \frac{3\pi}{2} (rejected) \: , \: \frac{\pi}{6}$

$so \: - \\ \\ = \cot(3 \alpha ) \\ \\ = \cot(3 \times \frac{\pi}{6} ) \\ \\ = 0$

HOPE YOU LIKE IT...