Question

if sin theta + cosec theta = 2 , find the value of sin²theta + cosec²theta​ . I have given the attachment picture​

Answer 1

Answer:given  

PERIMETER = 4 pie r

2 pie R = 4 pie r  

so R = 4pie r ÷ 2 pie  

R = 2r  

so AREA OF CIRCLE

= pie R^2

=pie (2r ×2r)

= pie ( 4r^2)

= 4 pie r^2

Step-by-step explanation:

Answer 2

sin∅ +cosec∅ =2

sin∅ + 1/sin∅ =2

sin²∅ +1 = 2sin∅

sin²∅ -2sin∅ +1 =0

(sin∅ -1)² =0

sin∅ = 1

hence ,

cosec∅ = 1

now,

sinⁿ∅ + cosecⁿ∅ = (1)ⁿ + (1)ⁿ =1 + 1 =2