If sin theta +cosec theta =2
then find ,
sin^n theta +cosec^n theta,
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give a brief explanation
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Answered by
1
Answer:
Answer is. 2....
Step-by-step explanation:
Square both side...
(sinn+cosecn) ^2=(2)^2
Sin^2n+cisec^2n+2xsinnxcosecn=4
Sin^2n+cosec^2n+2x1=4....(sinxcosec=1)
Sin^2n+cosec^2n=4-2=2...........
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