Question

if sin theta + cosec theta = 2 , then prove that sin^99 theta + cosec^99 theta =2​

Answer 1

Step-by-step explanation:

sin θ + cosec θ = 2

sin θ + (1/sin θ) – 2 = 0

sin2θ + 1 – 2 sin θ = 0

(sin θ – 1)2 = 0

sin θ – 1 = 0

sin θ = 1

cosec θ = 1/sin θ = 1

sin⁹⁹θ + cosec⁹⁹θ = (1)⁹⁹ + (1)⁹⁹= 1 + 1 = 2

Lhs=Rhs

hope you are satisfied with the answer

mark is as brainlist answer

because typing maths is not so easy////

Answer 2

Step-by-step explanation:

sin∅+cosec∅=2

sin∅+1/sin∅=2

(sin²∅+1)/sin∅=2

sin²∅+1= 2sin∅

sin²∅+1-2sin∅=0

(sin∅-1)²=0

sin∅-1=0

sin∅=1

sin∅= sin 90

∅= 90

sin⁹⁹∅+cos⁹⁹∅= 2

sin⁹⁹90+cos⁹⁹90=2

1⁹⁹+1⁹⁹=2

1+1=2

2=2

hence proved.

#666