Question

if sin theta equal to 24 by 25 then find the value of sin square theta + cos square theta

Answer 1

Heya !!




Sin theta = 24/25 = P/H



P = 24 and H = 25





B² = (H)² - (P)²



B² = (25)² - (24)²



B² = 49


B = √49 = 7


Therefore,


Cos theta = B/H = 7/25




Sin² Theta = (24/25)² = 576/625



And,


Cos² theta = (7/25)² = 49/625





Sin² theta + Cos² theta = 576/625 + 49/625 = 625/625 = 1.




Hence,



Sin² theta + Cos² theta = 1.

Answer 2

Step-by-step explanation:

Sin0=perpendicular/base

SinA=AB/AC = 24/25

Then u use pythagouras theorm;

(ac) sq= (ab) sq +(bc) sq