Math, asked by henafathima529, 8 months ago

if sin theta equal to 3 by 5 find the value of tan theta + sin theta whole square

Answers

Answered by anindyaadhikari13
4

 \sin\theta = \frac{3}{5}

Or,

 \sin^{2} \theta =  \frac{9}{25}

We know that,

 \sin^{2} \theta +  \cos^{2} \theta = 1

Or,

 \cos^{2} \theta = 1 -  \sin^{2} \theta

 = 1 -  \frac{9}{25}

 =  \frac{16}{25}

Or,

 \cos\theta =  \frac{4}{5}

Now,

 \tan \theta =  \frac{ \sin \theta}{ \cos \theta }

 =   \frac{\frac{3}{5} }{ \frac{4}{5} }

 =  \frac{3}{4}

Now,

 { (\tan \theta +  \sin \theta)}^{2}

 =  {( \frac{3}{4} +  \frac{3}{5}) }^{2}

 =  {(\frac{(3 \times 5) + (3 \times 4)}{20})}^{2}

 =  (\frac{15 + 12}{20})^{2}

 =  \frac{27^{2} }{ {20}^{2} }

 =  \frac{729}{400}

Hence, the answer is  \frac{729}{400}

Answered by Anonymous
3

Answer:

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Step-by-step explanation:

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