Question

If sin theta is 1/√2 then what is cos theta​

Answer 1

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$If \: sinθ \: is \: \dfrac{ 1}{√2} \: then \: what \: is \: cosθ$

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$\green{sinθ = }\purple{\dfrac{1}{√2} }\green{ =\dfrac{opposite \: to \: \angle\theta}{hypotenuse}}$

Now refer the fig

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So,

$\orange{AB² = AC²-CB²}$

$\orange{AB² = √2²-1}$

$\orange{AB² = 2-1}$

$\orange{AB² = 1}$

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Therefore,

$\green{cos\theta \: =\dfrac{adjacent \: to \: \angle\theta}{hypotenuse}}$

$\purple{\dfrac{1}{ \sqrt{2}}}$

[Hope this helps you.../]

Answer 2

Step-by-step explanation:

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