Question

If sin theta is equal to 12 by 13 find the value of sin theta minus cos square theta upon 2 sin theta minus cos theta into 1 upon tangent theta

Answer 1

$\sin( \alpha ) = \frac{12}{13} = \frac{p}{h}$

${h}^{2} - {p}^{2} = {b}^{2}$

${13}^{2} - {12}^{2} = {b}^{2}$

$169 - 144 = {b}^{2}$

$25 = {b}^{2}$

$5 = b$

$\frac{ \sin( \alpha ) - { \cos( \alpha ) }^{2} }{2 \sin( \alpha ) - \cos( \alpha ) } \times \frac{1}{ \tan( \alpha ) }$

$\frac{ \frac{12}{13} - { (\frac{5}{13} )}^{2} }{2 \times \frac{12}{13} - \ \frac{5}{13} } \times \frac{1}{ \frac{12}{5} }$

$\frac{ \frac{156 - 25}{169} }{ \frac{24 - 5}{13} } \times \frac{5}{12}$

$\frac{ \frac{131}{13} }{19} \times \frac{5}{12}$

$\frac{131 \times 19}{13} \times \frac{5}{12}$

$\frac{131 \times 19 \times 5}{13 \times 12}$

$\frac{12445}{156}$

$79.77$

hope this answer is helpful

Answer 2

Answer:

its helpful

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