Question

if sin theta is equal to 3/4 prove that root over cosec square minus cot square theta by secsquare theta minus 1 is equal to root 7by 3 .. plz answer it​

Answer 1

Answer:

Step-by-step explanation:

1. sintheta = 3/4   2.√cosec²theta-cot²theta÷sec²-1 = √7/3

3. now, √1/sin²theta-cos²theta/sin²theta divided by 1/cos²theta-1=√7/3

4. √1-cos²theta/√sin²theta÷1-cos²theta/cos²theta=√7/3

5. sin²theta/sintheta÷sin²theta/costheta=√7/3

6. sintheta/costheta=√7/3

7. tantheta=√7/3

8. √7/3=√7/3

here, sintheta=3/4

then, tantheta=√7/3

hence proved

√7/3