Question

if sin theta is equal to 3 by 4 find root of secant theta minus square theta by secant squared theta minus one​

Answer 1

$\sin \alpha = \frac{3}{4} = > \csc\alpha = \frac{4}{3}$

Now,

$\frac{ { \sec }^{2} \alpha }{ { \sec }^{2} - 1} = \frac{ { \sec }^{2} \alpha }{ { \tan }^{2} \alpha } \\ \\ = > \frac{ \frac{1}{ { \cos}^{2} \alpha } }{ \frac{ { \sin }^{2} \alpha }{ { \cos }^{2} \alpha } } \\ \\ = > \frac{1}{ { \sin }^{2} \alpha } = { \csc }^{2} \alpha = {( \frac{4}{3}) }^{2} = \frac{16}{9}$

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Answer 2

Answer:

Step-by-step explanation:

SEE THE ATTACHMENT!!!