if sin theta is equal to 3 by 5 then find cos theta
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sin theta = 3/5
P/H = 3 / 5
P = 3
H = 5
B = H ^2 - P ^ 2
B = 5 ^ 2 - 3 ^ 2
B = 4
cos theta = B/H
cos theta = 4/ 5
P/H = 3 / 5
P = 3
H = 5
B = H ^2 - P ^ 2
B = 5 ^ 2 - 3 ^ 2
B = 4
cos theta = B/H
cos theta = 4/ 5
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