Question

if sin theta is equal to 4 upon 5 then find the value of cos square theta + tan theta minus cot theta upon sec theta​

Answer 1

Given :-

• sin θ = (4/5) .

To Find :-

• (cos²θ + tan θ - cot θ) / sec θ = ?

Answer :-

→ sin θ = 4/5 = perpendicular / hypotenuse / P / H

so,

→ B = √(H² - P²) { By pythagoras theorem .}

→ B = √(5² - 4²) = √(25 - 16) = √9 = 3

then,

• cos θ = B/H = 3/5
• tan θ = P/B = 4/3
• cot θ = B/P = 3/4
• sec θ = H/B = 5/3

putting all values we get,

→ [(3/5)² + (4/3) - (3/4)] / (5/3)

→ [(9*12 + 4*100 - 3*75) /25*3*4)] / (5/3)

→ (108 + 400 - 225)/300 / (5/3)

→ (283/300) * (3/5)

→ (283/500) (Ans.)

Learn more :-

It sino + tano = m

tano - sino an

Then express the

values of m²-n² in terms

of M and N

https://brainly.in/question/13926306

tanA/(1-cotA) + cotA/(1-tanA)

https://brainly.in/question/16775946