Question

If sin theta is x/y then cos 'theta' is

Answer 1

Answer:

We have a relation, Sin^2 X + Cos^2 X = 1,

So, by using this relation,

Cos X = root [1 - X^2/ Y^2]

Cos X = root [ (Y^2 - X^2)/Y^2]

And tan X = Sin X / Cos X

= (X *Y) / root ( Y^2 - X^2)

Answer 2

Answer:

$\sqrt{y^2-x^2} / y$

Step-by-step explanation:

sinθ = (opposite side)/(hypotenuse) = x/y

=> adjacent side = $\sqrt{(hypotenuse)^2 - (opposite side)^2}$ = $\sqrt{y^2 - x^2}$

then, cosθ = (adjacent side)/(hypotenuse) = $\sqrt{(y^2 - x^2)} / y$