If sin theta= m/n find the value tan theta+4/4cot theta+1
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sin∅ = m/n
therefore, here opposite side of ∅ is m & hypotenuse is n
so, the adjacent side will be,
√n²-m². (pythagoras theorem)
tan∅ = opposite/adjacent = m/√n²-m²
cot∅ = adjacent/opposite = √(n²-m²)/m
We have to find, (tan∅+4)/(4cot∅+1)
so, the value will be,
[m/√(n²-m²)]
therefore, here opposite side of ∅ is m & hypotenuse is n
so, the adjacent side will be,
√n²-m². (pythagoras theorem)
tan∅ = opposite/adjacent = m/√n²-m²
cot∅ = adjacent/opposite = √(n²-m²)/m
We have to find, (tan∅+4)/(4cot∅+1)
so, the value will be,
[m/√(n²-m²)]
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Hiteshbehera74:
yup
Answered by
6
Here is your answer my friend :)
Hope it'll help you
Hope it'll help you
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