Question

If sin theta =m/n ,then find cos theta

Answer 1

here is the answer hope it will help..

Answer 2

Answer:

Required value of $cos \theta$ is $\frac{ \sqrt{ {n}^{2} - {m}^{2} } }{n}$

Step-by-step explanation:

Given,

$\sin(\theta) = \frac{m}{n}$

We want to find value of $\cos(\theta)$

We know,

${cos}^{2} \theta + {sin}^{2} \theta = 1 \\ {cos}^{2} \theta = 1 - {sin}^{2} \theta \\ \cos(\theta) = \sqrt{1 - {sin}^{2}\theta} \\ = \sqrt{1 - { (\frac{m}{n} )}^{2} } \\ = \sqrt{1 - \frac{ {m}^{2} }{ {n}^{2} } } \\ = \sqrt{ \frac{ {n}^{2} - {m}^{2} }{ {n}^{2} } } \\ = \frac{ \sqrt{ {n}^{2} - {m}^{2} } }{n}$

This is a problem of Trigonometry.

Some important Trigonometry formulas:

$sin(x) = \cos(\frac{\pi}{2} - x) \\ \tan(x) = \cot(\frac{\pi}{2} - x) \\ \sec(x) = \csc(\frac{\pi}{2} - x) \\ \cos(x) = \sin(\frac{\pi}{2} - x) \\ \cot(x) = \tan(\frac{\pi}{2} - x) \\ \csc(x) = \sec(\frac{\pi}{2} - x)$

know more about Trigonometry,

https://brainly.in/question/8632966

https://brainly.in/question/11371684

#SPJ3