if sin theta minus cos theta = half, then find value of sin theta plus cos theta
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sin theta - cos theta = 1/2
(sin theta - cos theta)^2= sin^2theta +cos^2theta -2costheta x sintheta
1/4 = 1 -2costheta x sin theta
2 cos theta x sin theta= 1- 1/4 = 3/4
(sin theta +cos theta)^2= sin^2 theta + cos^2theta +2sintheta x cos theta
= 1+ 3/4 = 7/4
Therefore, sin theta + cos theta = root of 7/2
(sin theta - cos theta)^2= sin^2theta +cos^2theta -2costheta x sintheta
1/4 = 1 -2costheta x sin theta
2 cos theta x sin theta= 1- 1/4 = 3/4
(sin theta +cos theta)^2= sin^2 theta + cos^2theta +2sintheta x cos theta
= 1+ 3/4 = 7/4
Therefore, sin theta + cos theta = root of 7/2
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Answer:
Step-by-step explanation:
Sin theta-cos theta=1/2,then
sin theta +cos theta=1
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