Question

If sin theta=p/q, then cos theta =​

Answer 1

Answer:

$\text{cos }\theta=\sqrt{\frac{q^2-p^2}{q} }$

Step-by-step explanation:

If $\text{sin }\theta=\frac{p}{q}$

Then perpendicular =p and hypotenuse=q.

Therefore, according to Pythagoras theorem base =$\sqrt{q^2-p^2}$

$\text{cos }\theta=\frac{\text{base}}{\text{hypotenuse}}\\\text{cos }\theta=\frac{\sqrt{q^2-p^2}}{q}$

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