Question

If sin theta =root 2 -1 then find sec(90-theta)

Answer 1

Answer:

The answer is

Step-by-step explanation:

Sec(90-theta) will be 1/root2-1 as sec is positive in first quadrant and it's just function changes

Answer 2

The value of  $\sec(90-\theta)$ $= \dfrac{1}{\sqrt{2}-1}$

Step-by-step explanation:

We have,

$\sin \theta =\sqrt{2}-1$       ........ (1)

To find, the value of $\sec(90-\theta)=?$

∴ $\sec(90-\theta)$

Using the trigonometric identity,

$\sec(90-\theta)=\csc \theta$

= $\csc \theta$

Using the trigonometric identity,

$\csc \theta=\dfrac{1}{\sin \theta}$

$=\dfrac{1}{\sin \theta}$

From equation (1), we get

$= \dfrac{1}{\sqrt{2}-1}$

∴ The value of  $\sec(90-\theta)$ $= \dfrac{1}{\sqrt{2}-1}$