if sin theta-route3 cos theta=0 then find the value of theta.
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let this theta be A for simplicity then
➡sinA-√3cosA=0
➡sinA=√3cosA
➡sinA/cosA=√3
➡tanA=tan60 (tan60=√3)
➡A=60°
hence value of theta is 60°
➡sinA-√3cosA=0
➡sinA=√3cosA
➡sinA/cosA=√3
➡tanA=tan60 (tan60=√3)
➡A=60°
hence value of theta is 60°
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