Question

if sin(theta)=s, cos(theta)=r;7s^2+3r^2=4​ plz g com​

Answer 1

Given: sin(Θ)=s and cos(Θ)=r equation is 7s²+3r²=4

To find: Theta value (Θ) also s and r can be found out

Solution :

We know that sin(Θ)²+cos(Θ)²=1 ==>s²+r²=1

Hence -> cos(Θ)²=1-sin(Θ)²

Substitute in the equation given:

7s²+3r²=4

7s²+3(1-s²)=4

4s²+3=4

4s²=1

s=1/2

r²=1-s²=1-(1/2)²=√3/2

theta is sin(Θ)=1/2 which is 30degree.

Final Answer: s=1/2 r=√3/2 theta=30degree