if sin theta+sin^2theta=1 so prove cos^theta+cos^4 theta=1
deepak448:
can u tell me this ques. came frm which book!!
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Answered by
3
sin (theta) +sin ^2 (theta) =1
sin (theta) +1-cos ^2 (theta) =1
sin (theta) -cos ^2 (theta) =0
sin (theta) =cos ^2 (theta)
square both sides
sin^2 (theta) =cos ^4 (theta)
1-cos ^2 (theta)= cos ^4 (theta)
cos ^4(theta) + cos^ 2( theta) = 1
hope it will help you....!!!!
sin (theta) +1-cos ^2 (theta) =1
sin (theta) -cos ^2 (theta) =0
sin (theta) =cos ^2 (theta)
square both sides
sin^2 (theta) =cos ^4 (theta)
1-cos ^2 (theta)= cos ^4 (theta)
cos ^4(theta) + cos^ 2( theta) = 1
hope it will help you....!!!!
Answered by
6
HELLO DEAR,
We know that:-
sin² theta +cos ²theta =1
(1 - sin²theta ) =cos ²theta------(1)
given that:-
sintheta +sin²theta =1
=> sintheta= (1-sin²theta) ----------from(1)
=> sin theta = cos²theta [ squaring both side]
=> sin²theta = cos⁴theta
=> 1 - cos²theta = cos⁴theta ----------from--(1)
=> cos²theta + cos⁴theta =1
I HOPE ITS HELP YOU DEAR,
THANKS
We know that:-
sin² theta +cos ²theta =1
(1 - sin²theta ) =cos ²theta------(1)
given that:-
sintheta +sin²theta =1
=> sintheta= (1-sin²theta) ----------from(1)
=> sin theta = cos²theta [ squaring both side]
=> sin²theta = cos⁴theta
=> 1 - cos²theta = cos⁴theta ----------from--(1)
=> cos²theta + cos⁴theta =1
I HOPE ITS HELP YOU DEAR,
THANKS
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