Question

If sin theta+sin square theta=1 then find value of
Cos^12 theta+3cos^10theta3cos^8theta+cos^6theta+2cos^4theta+2cos^2theta-2
Plz make it as easier as u can..

Answer 1

Answer:

Step-by-step explanation:

Let theta =A

SinA+Sin^2A= 1

SinA=1-Sin^2A

SinA=Cos^2A

(Cos^12A+3Cos^10A+3Cos^8A+Cos^6A )+ (2Cos^4A+2Cos^2A-2)

(Cos^4A+Cos^2A)^3+2(Cos^4A+Cos^2A-1)

(Sin^2A+Cos^2A)^3+2(Sin^2A+Cos^2A-1)

=(1)^3+2(1-1)

=1+2*0

=1+0

=1

Note:

Cos^4A=Sin^2A