if sin theta + sin square theta equals to 1 then cos square theta + cos square theta +2 cos squared theta
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Given, sinθ+sin
2 θ=1
⇒sinθ=1−sin
2
θ=cos 2 θ
Therefore, cos
2
θ+cos
4
θ=cos
2
θ(1+cos
2
θ)
=sinθ(1+sinθ)
=sinθ+sin
2
θ
=1
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