if sin thete +sin²theta=1 them cos²theta +cos⁴theta=? I WILL MARK YOU THE BRANLIEST :).
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sin (theta) +sin ^2 (theta) =1
sin (theta) +1-cos ^2 (theta) =1
sin (theta) -cos ^2 (theta) =0
sin (theta) =cos ^2 (theta)
square both sides
sin^2 (theta) =cos ^4 (theta)
1-cos ^2 (theta)= cos ^4 (theta)
cos ^4 (theta)+cos ^2 (theta)=1
sin (theta) +1-cos ^2 (theta) =1
sin (theta) -cos ^2 (theta) =0
sin (theta) =cos ^2 (theta)
square both sides
sin^2 (theta) =cos ^4 (theta)
1-cos ^2 (theta)= cos ^4 (theta)
cos ^4 (theta)+cos ^2 (theta)=1
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Hoo answer is 1
it is our IIT book question
it is our IIT book question
vinay1739:
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