If sin thetha + cosec thetha =2 ,find the value of ( sin thetha square + cosec thetha square )
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Given
sin∅ + cosec∅ = 2
To find
(sin²∅ + cosec²∅)
sin∅ + cosec∅ = 2
Square both the sides
(sin∅ + cosec∅)² = (2)²
⇒ sin²∅ + cosec²∅ + 2sin∅cosec∅ = 4
(using, (a + b)² = a² + b² + 2ab)
⇒ sin²∅ + cosec²∅ + 2 sin∅(1/sin∅) = 4
(since, cosec∅ = 1/sin∅)
⇒ sin²∅ + cosec²∅ + 2 = 4
⇒ sin²∅ + cosec²∅ = 2
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