if sin theya=a/b,find se theya+tan theta
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Answer:
sec theta = 1/cos theta
tan theta = sin theta / cos theta
sec theta + tan theta = 1/ cos theta + sin theta / cos theta
=( sin theta +1)/cos theta
= a/b +1 / b^2 - a^2
= (a+b)/b ( b^2-a^2)
= (a+b) / b ^3 - a^2b
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